keywords
help--invokes the help system
helphelp wordHelp word sends a word to the help system.
The word is looked up in the nrn/lib/helpdict file and if found
Netscape is sent the appropriate URL to display
the help text. If the word is not found, the URL for the table
of contents is sent. Netscape must be running for the help system
to work.
keywords
returnreturn exprreturn command will immediately exit from a procedure
without returning a value.
The return expr command will immediately exit from a function
which must return a value. This command must also be the last executable
statement of a function. It is possible for a function to contain more
than one return command, for instance in a series of if else
statements; however, not more than one of the return commands may
return a value at any given time.
func max(){
if ($1 > $2){
return $1
} else {
return $2
}
}
max(3,6), where $1 is the
first argument (3) and $2 is the second argument (6). This use of max would return the value 6.
keywords
break
section { statement }
or the stack will not be properly popped. Also it should not be placed on a line that contains object syntax but should be placed on a line by itself. eg.
should be writtenx.p() break
x.p() break
while(1) {
x = fscan()
if (x < 0) {
break;
}
print sqrt(x)
}
keywords
continue
for i=1,10{
if(i==6){
continue
}
print i
}
You can accomplish the same thing with the following syntax:
for i=1,10{
if(i<6 || i>6){
print i
}
}
keywords
stop
keywords
if (expr) stmt1if (expr) stmt1 else stmt2else form, if the expression
evaluates to zero (false) stm2 is executed.
i = 0 //initialize i
j = 0 //initialize j
if(vec.x[i] <= 10 && i < vec.size()){ //if the value of the ith element in vec
//is less than or equal to 10, and
//if i is an index within vec
vec1.x[j] = vec.x[i] //set the jth element of vec1 equal to that
//ith element of vec
i = i+1 //increment i by 1
j = j+1 //increment j by 1
} else{ //otherwise (This must be on the same line as the closing brace of
//the previous statement in order to indicate that the compound
//statement has not ended.)
i = i+1 //simply go to the next element of vec
}
keywords
keywords
while (expr) stmt
numelements = 20
i = 0
while (i < numelements){
print(cos(vec.x[i]))
print(sin(vec.x[i]))
}
vec elements up to numelements, which in this case = 20.
keywords
for(stmt1; expr2; stmt3) stmtfor var=expr1, expr2 stmtfor (var) stmtfor (var, expr) stmtfor iterator (args) stmtfor statement is similar to while in that it iterates over
a statement. However, the for statement is more compact and contains within its parentheses
the command to advance to the next iteration. Statements 1 and 3 may be
empty.
This command also has a short form which always increments the iterations by one.
is equivalent tofor var=expr1, expr2 stmt
However, expr1 and expr2 are evaluated only once at the beginning of thefor(var=expr1; var <= expr2; var=var+1) stmt
for.
for (var) stmt
Loops over all segments of the currently accessed section. var begins at 0 and ends at 1. In between var is set to the center position of each segment. Ie. stmt is executed nseg+2 times.
for (var, expr) stmt
If the expression evaluates to a non-zero value, it is exactly equivalent
to
for (var) stmt
If it evaluates to 0 (within float_epsilon ) then the interation does
not include the 0 or 1 points. Thus for(x, 0) { print x }
is exactly equivalent to for (x) if (x > 0 && x < 1) { print x }
The iterator form of the for loop executes the statement with a looping construct defined by the user.
for(i=0; i<=9; i=i+1){
print i*2
}
for i=0, 9 {
print i*2
}
create axon
access axon
{nseg = 5 L=1000 diam=50 insert hh }
for (x) print x, L*x
for (x) if (x > 0 && x < 1) { print x, gnabar_hh(x) }
keywords
print expr, string, ...
printsx=2 y=3 print x, "hello", "good-bye", y, 7
and then moves to the next line.x hello good-bye 3 7
keywords
delete varname
keywords
read varread var
will return 0 on
end of file and 1 otherwise.
for i=1, 5 {
read x
print x*x
}
keywordsA toggle for parser debugging purposes. Prints the stack machine commands resulting from parsing a statement. Not useful to the user.
keywords
double var1[expr]double var2[expr1][expr2]double varn[expr1][expr2]...[exprn]The index for each dimension ranges from 0 to expr-1. Arrays may be redeclared at any time, including within procedures. Thus arrays may have different lengths in different objects.
The Vector class for the ivoc interpreter provides convenient and powerful methods for manipulating arrays.
declares an array with 40 elements, whereasdouble vec[40]
creates a vector (which is an array by a different name) with 40 elements which you can manipulate using the commands of the Vector class.objref vec vec = new Vector(40)
keywords
emThis is a reasonably complete editor with many commands. These commands are listed in emacs.txt. A tutorial is also available at emacstut.txt
When called from the interpreter, the command ^C immediately returns to the interpreter and the current buffer is interpreted. Other commands follow:
keywords
depvar
depvar x, y, z
proc equations() {
eqn x:: x + 2*y + z = 6
eqn y:: x - y + z = 2
eqn z:: 2*x + y -z = -3
}
equations()
solve()
print x,y,z
keywords
eqn var:: expr = expreqn var: expr =eqn var: = expr
eqinit()
depvar x, y, z
proc equations() {
eqn x:: x + 2*y + z = 6
eqn y:: x - y + z = 2
eqn z:: 2*x + y -z = -3
eqn z: = 5 + 4y
}
equations()
solve()
print x,y,z
keywords
local var
func count() {local i, x
x = 0
for i=0,40 {
if (vec.x[i] == 7) {
x = x+1
}
}
return x
}
vec. i
and x are local variables, and their usage here will not affect variables of the same name in
other functions and procedures of the same program.
keywords
strdef stringname
will print to the screen:strdef a, b, c a = "Hello, " b = "how are you?" c = "What is your name?" print a, b print c
Hello, how are you? What is your name?
keywords
setpointer pvar varwould enable the synapse in soma1 to observe the axon2 membrane potential.soma1 syn1=new synp(.5) setpointer syn1.vpre, axon2.v(1)
keywords
insert mechanism
keywords
uninsert mechanism